Question 1.6) Four point charges qA 2 μC qB 5 μC, qC 2 μC, and qD 5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of

A square ABCD with each side = 10 cm = 0.1 m (divide by 100 to convert cm to m ) Charge qA = 2 µC, qB = −5 µC, qC = 2 µC, and qD = −5 And 1 µC placed at the centre of the square

q1 = first charge
q2 = Second charge
r = distance between both charge
ε0= permittivity of free space

F_{O A} = \frac{1}{4 π \in O} |\frac{1}{O A^{2}}|

We know that OA = OC hence
FOA = - FOC
FOA + FOC = 0
Similarly
FOB + FODC = 0
Similarly other forces will also cancel out to each other FTOTAL =0
Hence sum of all forces w =0

Question 1.6) Four point charges qA 2 μC qB 5 μC, qC 2 μC, and qD 5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of- Hosting Precise

Posted on 2nd Oct 2021 01:21:10 in

Question 1.6) Four point charges qA = 2 μC, qB = –5 μC, qC = 2 μC, and qD = –5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of the square?

Ans:-

A square ABCD with each side = 10 cm = 0.1 m (divide by 100 to convert cm to m ) Charge qA = 2 µC, qB = −5 µC, qC = 2 µC, and qD = −5 And 1 µC placed at the centre of the square

Apply Coulomb’s law

$F = \frac{1}{4 π \in o}$

$|\frac{q_{1} q_{2}}{r^{2}}|$

q1 = first charge
q2 = Second charge
r = distance between both charge
ε0= permittivity of free space

$F_{O A} = \frac{1}{4 π \in O} |\frac{1}{O A^{2}}|$

$F_{O A} = \frac{1}{4 π \in O} |\frac{1}{O C^{2}}|$

We know that OA = OC hence
FOA = - FOC
FOA + FOC = 0
Similarly
FOB + FODC = 0
Similarly other forces will also cancel out to each other FTOTAL =0
Hence sum of all forces w =0

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